science:physics
Table of Contents
physics
see also:
Introduction
a few basic equations
- velocity
- velocity = distance travelled / unit time
- 100kph = 100kph x 1000m / (3600secs) = 27.8m/s
- acceleration
- acceleration = velocity change / unit time
- a car accelerating uniformly from 0 to 100kph in 10secs will have:
- average acceleration = 100kph x 1000m / (3600secs x 10secs) = 2.78m/second2
- momentum
- linear momentum = mass x velocity
- angular momentum = the moment of inertia (I) x angular velocity (ω)
- moment of inertia (I) = mass x radius2 where radius is distance to the centre of motion
- hence a ballerina will spin faster when limbs are close to the body as moment of inertia is reduced and thus angular velocity must increase as momentum remains constant
- NB. momentum is conserved during collisions, explosions, and other events involving objects in motion, however, in the real world, some kinetic energy is lost to heat during a collision, especially if the collision is inelastic, and thus overall momentum will fall.
- net system momentum is constant if the net external force (or for angular momentum, external torque) is zero
- force
- force = mass x acceleration = change in momentum / unit time
- 1 newton (N) = 1 kilogram X meter/second2
- lifting a 1kg object to overcome gravity requires a force of 1kg x acceleration due to gravity = 9.8N
- force to move a 2000kg car from 0 to 100kph in 10secs = 2000 x 2.78 = 5556N
- kinetic energy
- energy = 1/2 x mass x velocity2
- 1 Joule = 1 kg m2/sec2
- gravitational potential energy
- energy = mass x gravitational constant x height
- work
- work = force x distance = change in kinetic energy
- 1 Joule = 1Nm
- work done to lift a 10kg object 1m off the ground = 10kg x 9.8 x 1m = 100J
- work done to accelerate a 2000kg car from 0 to 100kph (excl. frictional and wind resistance work) = 0.5 x 2000 x (27.8m/s)2 = 27,800J
- power
- power = work / time taken = energy used / time
- 1W = 1 Joule/sec
- power to accelerate a 2000kg car from 0 to 100kph in 10sec = 27,800J / 10sec = 2780W
- note that combustion engines are only about 40% efficient so the engine would actually need to use 2780/0.4 =7kW of power
- petrol has a energy density of 44MJ/kg thus over 10sec at 7000W requires 70000J = 70kJ and thus ~44000/70 = 1.6mL of fuel IF there were no frictional forces to overcome such as wind resistance, etc.
electricity
- see also electricity in Australia
- electrical power
- watts = current in amps x voltage
- energy capacity of a battery
- capacity is measured in Watt-hours (Wh) ie. how many watts of power is available over 1 hour
- watt-hours = amp-hours x nominal voltage
- ie. a 100Ah 12.8V lithium battery will have capacity of 100 x 12.8 = 1280Wh and thus will last 12.8 hours if using 100W of power
- Ohm's law
- voltage difference between two points in a circuit (volts) = current (amps) x resistance (ohms)
heat
- heat energy required to heat a substance
- heat energy = mass x specific heat x change in temperature in deg C
- eg. water has specific heat of 4,180J/kg°C
- eg. cast iron and stainless steel has specific heat of ~500J/kg°C
- Stefan–Boltzmann law for rate of radiant heat loss from a surface
- radiant heat loss in watts = ϵσA(T14−T24)
- where,
- ϵ is the emissivity of the surface (dimensionless, between 0 and 1)
- σ is the Stefan-Boltzmann constant (5.67×10−8 W m−2K−4)
- A is the surface area (in square meters)
- T1 is the absolute temperature of the radiating surface (in kelvin)
- T2 is the absolute temperature of the surroundings (in kelvin)
- Wien's displacement law for frequency of light emitted from a black body
- peak frequency of light =2.82kBT/h
- where,
- kB is Boltzmann's constant (1.38×10−23J/K
- T is the absolute temperature in kelvin
- h is Planck's constant (6.63×10−34 J·s)
flow of fluids
- laminar flow
- there is minimal mixing between layers of the fluid and there is very little fluctuation of the speed of the flow
- blood flow in arteries is generally laminar
- turbulent flow
- there is increasing mixing of the layers of flow with eddy formation resulting in varying flow rates - the greater the variation in flow, the greater the turbulence
- energy cascade: turbulence converts kinetic energy into heat via the creation of ever smaller eddies and eventually dissipates due to viscosity
- turbulence is complex and varies over both spatial and time dimensions
- direct numerical simulation (DNS) can be used to model this but it is computationally complex to calculate, instead large eddy simulation (LES) is often used instead which uses a sub-grid scale model to address the small eddies
- the Reynolds-averaged Navier-Stokes technique is the least computationally expensive model technique but this only models the effects of eddies using turbulent viscosity, not the actual eddies
- given the computational complexity, wind tunnels are often used to assess the effect of wind on objects such as aerodynamic vehicles, tents, etc
- turbulent flow requires more energy and results in a greater pressure drop
- most flows in nature are turbulent
- Reynold's number
- a value for a given system which means turbulent flow is likely to occur if Reynold's number is high for a given system
- Reynold's number (Re) = fluid density x velocity x characteristic length / dynamic viscosity = velocity x length / kinematic viscosity = inertial forces / viscous forces
- for flow past a cylinder, characteristic length = cylinder diameter
- for flow past a air foil (wing of an airplane), characteristic length = length
- for flow through a pipe:
- characteristic length = pipe diameter
- turbulent flow is likely if Re > 2000-4000
- in laminar flow, flow rate at the pipe wall is zero in “no-slip condition” and velocity increases to a maximum at the centre of the pipe and the velocity profile is parabolic
- in turbulent flow, flow rate at the pipe wall is zero in “no-slip condition” (there is a laminar sublayer here but its thickness decreases as Re increases) however, away from the wall, flow rate is more even throughout the pipe due to the mixing of layers creating a more homeogenous time averaged flow velocity but with more random variations
- if the pipe wall roughness thickness is less than the laminar sublayer thickness then the pipe is said to be hydraulically smooth as it will not effect the turbulent flow
- Darcy-Weisbach equation to calculate pressure drop along a pipe
- pressure drop = length of pipe x Darcy friction factor x (density/2) x (avg velocity)2/hydraulic diameter
- for laminar flow, Darcy friction factor = 64/Re
- for turbulent flow, there is a complicated Colebrook equation to determine the friction factor which requires an iterative calculation hence it is generally looked up on a Moody Diagram, but simplified pressure drop is proportional to velocity squared and pipe surface roughness
- Bernoulli principle and equation
- for incompressible, non-viscous fluids:
- fluid flow speed2/2 +gz + static pressure/density = constant
- g = acceleration due to gravity
- z = the elevation of the point above a reference plane
- when applied to determine the static pressure drop when fluid flows faster through a narrowing in a pipe (the Venturi effect), the equation becomes:
- pressure drop = density x (velocity22 - velocity12)/2
- as flow rate is equal in each pipe section, velocity2 x pipe area2 = velocity1 x pipe area1 (see also https://en.wikipedia.org/wiki/Venturi_effect))
- see https://en.wikipedia.org/wiki/Bernoulli%27s_principle for more detail
science/physics.txt · Last modified: 2025/11/06 12:38 by gary1